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Proof step 4 from proof nodes-append (previous step)

st[n] = mkblock(x, lax, m0), inv(mkblock(x, lax, m0)), n ∈ st ⊦ nodes(st[n, mkblock(x + a ', lax + @(m, m2) ', m1)]) = nodes(st)[@(n, m, m2), a], @(m, m2) ∈ lax

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ ast = ast0 ↔ (∀ adr. (adr ∈ ast ↔ adr ∈ ast0) ∧ (adr ∈ ast → ast[adr] = ast0[adr]))
Proof step 6:
st[n] = mkblock(x, lax, m0), inv(mkblock(x, lax, m0)), n ∈ st ⊦ @(m, m2) ∈ lax, ∀ adr. (adr ∈ nodes(st[n, mkblock(x + a ', lax + @(m, m2) ', m1)]) ↔ adr ∈ nodes(st)[@(n, m, m2), a]) ∧ ( adr ∈ nodes(st[n, mkblock(x + a ', lax + @(m, m2) ', m1)]) → nodes(st[n, mkblock(x + a ', lax + @(m, m2) ', m1)])[adr] = nodes(st)[@(n, m, m2), a][adr])

Rule argument

spec: store, inst: address-store name: k-Extension seq: ⊦ ast = ast0 ↔ (∀ adr. (adr ∈ ast ↔ adr ∈ ast0) ∧ (adr ∈ ast → ast[adr] = ast0[adr])) subst: [ast0, ast] → [nodes(st)[@(n, m, m2), a], nodes(st[n, mkblock(x + a ', lax + @(m, m2) ', m1)])] flags: <all paths>

Additional information

Used terms: nodes(st)[@(n, m, m2), a], nodes(st[n, mkblock(x + a ', lax + @(m, m2) ', m1)])