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Proof step 7 from proof notin-add-diff-dom-nodes (previous step)

⊦ adr0 ∈ as ++ adr ∧ ¬ adr0 ∈ dom nodes(st) ↔ adr0 = adr ∨ adr0 ∈ as \ dom nodes(st), adr ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: in-nodes: ⊦ adr ∈ nodes(st) ↔ adr ∈ st;% ⊦ adr ∈ as ++ adr0 ↔ adr = adr0 ∨ adr ∈ as; (s)% ⊦ adr ∈ as \ as0 ↔ adr ∈ as ∧ ¬ adr ∈ as0; (ws)% ⊦ adr ∈ dom ast ↔ adr ∈ ast; (s)% ⊦ adr ≠ adr0 → (adr ∈ as ++ adr0 ↔ adr ∈ as); (s)