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Proof step 28 from proof prefix-subseteq-dom-nodes-rev (previous step)

st1[m] = mkblock(x0, lax0, m3), st0[m] = mkblock(x, lax, m2), m ∈ st0, @(m0, m1) ∈ lax, m ∈ st0 → m ∈ st1, ∀ n. n ∈ st0 ∧ n ∈ st1 → st0[n].list ⊑ st1[n].list ∧ st0[n].ladrlist ⊑ st1[n].ladrlist ∧ # st0[n].list = # st0[n].ladrlist ∧ # st1[n].list = # st1[n].ladrlist ⊦ m ∈ st1 ∧ @(m0, m1) ∈ lax0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
st0[m] = mkblock(x, lax, m2), st1[m] = mkblock(x0, lax0, m3), @(m0, m1) ∈ lax, m ∈ st0, m ∈ st1, ∀ n. n ∈ st0 ∧ n ∈ st1 → st0[n].list ⊑ st1[n].list ∧ st0[n].ladrlist ⊑ st1[n].ladrlist ∧ # st0[n].list = # st0[n].ladrlist ∧ # st1[n].list = # st1[n].ladrlist ⊦ @(m0, m1) ∈ lax0

Proof step 28 from proof prefix-subseteq-dom-nodes-rev (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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