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Proof step 1 from proof addresslist-in-lnum-simp (conclusion)

⊦ @(n0, n1, n2) ∈ lax.to-adr(n) ↔ n0 = n ∧ @(n1, n2) ∈ lax

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: to-adrs-in: ⊦ @(m, m0, m1) ∈ lax.to-adr(n) ↔ m = n ∧ @(m0, m1) ∈ lax;