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Proof step 2 from proof addresslist-length (previous step)

∀ n. # lax0.to-adr(n) = # lax0 ⊦ # (ladr + lax0).to-adr(n) = #(ladr + lax0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ n. # lax0.to-adr(n) = # lax0 ⊦ # lax0.to-adr(n) = # lax0

Rule argument

Additional information

Used simplifier rules: adrs-rec: ⊦ (ladr ' + lax).to-adr(n) = @(n, ladr.off, ladr.size) + lax.to-adr(n);%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + n = m + n0 ↔ n = n0; (s)% ⊦ #(ladr ' + lax) = (# lax)+1; (s)%a: ⊦ (ax + ax0) + ax1 = ax + ax0 + ax1; from specification list[address-list-set]% ⊦ m +1 = m + 1; (s)% ⊦ #(adr ' + ax) = (# ax)+1; (s)%a: ⊦ (lax + lax0) + lax1 = lax + lax0 + lax1; from specification list[laddress-list]% ⊦ adr + ax = adr ' + ax; (s)% ⊦ ladr + lax = ladr ' + lax; (s)