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Proof step 1 from proof at-dealloc (conclusion)

⊦ n ≠ m ∧ @(m, m0, m1) ∈ st → (st -- n)[@(m, m0, m1)] = st[@(m, m0, m1)]

System applied rule normalize

And obtained the following new goals

Proof step 2:
@(m, m0, m1) ∈ st ⊦ (st -- n)[@(m, m0, m1)] = st[@(m, m0, m1)], n = m

Rule argument

Additional information