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Proof step 4 from proof at-dealloc (previous step)

st[m] = mkblock(x, lax, m2), @(m0, m1) ∈ lax, m ∈ st ⊦ (st -- n)[@(m, m0, m1)] = x[pos(@(m0, m1), lax)], n = m

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: at seq: ⊦ adr ∈ st → st[adr] = st[adr.lnum].list [pos(@(adr.pos, adr.size), st[adr.lnum].ladrlist) ] subst: [adr, st] → [@(m, m0, m1), st -- n] flags: <all paths>

Additional information

Used simplifier rules: in-dealloc: ⊦ adr ∈ st -- n ↔ adr ∈ st ∧ adr.lnum ≠ n;%in: ⊦ adr ∈ st ↔ adr.lnum ∈ st ∧ @(adr.pos, adr.size) ∈ st[adr.lnum].ladrlist;% ⊦ @(m, m0, m1).lnum = m; (s)% ⊦ n ≠ n0 → (st -- n0)[n] = st[n]; (s)% ⊦ @(m, m0, m1).pos = m0; (s)% ⊦ @(m, m0, m1).size = m1; (s)% ⊦ mkblock(x, lax, m).list = x; (s)% ⊦ mkblock(x, lax, m).ladrlist = lax; (s) Used terms: @(m, m0, m1), st -- n