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Proof step 10 from proof at-store-inv (previous step)

∀ n0. n0 ∈ st → # st[n0].list = # st[n0].ladrlist ∧ inv-flashsize(st[n0].list, st[n0].ladrlist) ∧ ¬ dups(st[n0].ladrlist), ∀ n0. n0 ∈ st[n, mkblock(x, lax, m)] → inv-flashsize(st[n, mkblock(x, lax, m)][n0].list, st[n, mkblock(x, lax, m)][n0].ladrlist) ∧ ¬ dups(st[n, mkblock(x, lax, m)][n0].ladrlist) ⊦ inv-flashsize(x, lax)

Heuristic quantifier applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: n

Additional information

Used simplifier rules: ⊦ n ∈ st[n, ablock]; (s)% ⊦ st[n, ablock][n] = ablock; (s)% ⊦ mkblock(x, lax, m).list = x; (s)% ⊦ mkblock(x, lax, m).ladrlist = lax; (s) Used terms: n