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Proof step 6 from proof at-write-refsize (previous step)

st[m0] = mkblock(x, lax, m3), @(m1, m2) ∈ lax, m0 ∈ st, n ∈ st ⊦ st[n, st[n].ref-size:= m][@(m0, m1, m2)] = x[pos(@(m1, m2), lax)]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ adr ∈ st → st[adr] = st[adr.lnum].list[pos(@(adr.pos, adr.size), st[adr.lnum].ladrlist)]
Proof step 8:
st[m0] = mkblock(x, lax, m3), n ∈ st, m0 ∈ st, @(m1, m2) ∈ lax, @(m0, m1, m2) ∈ st[n, st[n].ref-size:= m] ⊦ st[n, st[n].ref-size:= m][@(m0, m1, m2).lnum].list [pos(@(@(m0, m1, m2).pos, @(m0, m1, m2).size), st[n, st[n].ref-size:= m][@(m0, m1, m2).lnum].ladrlist) ] = x[pos(@(m1, m2), lax)]

Rule argument

spec: <toplevel> name: at seq: ⊦ adr ∈ st → st[adr] = st[adr.lnum].list [pos(@(adr.pos, adr.size), st[adr.lnum].ladrlist) ] subst: [adr, st] → [@(m0, m1, m2), st[n, st[n].ref-size:= m]] flags: <all paths>

Additional information

Used simplifier rules: in-write-refsize: ⊦ n ∈ st → (adr ∈ st[n, st[n].ref-size:= m] ↔ adr ∈ st);%in-in-adr: ⊦ st[n] = mkblock(x, lax, m0) ∧ n ∈ st ∧ @(n0, n1) ∈ lax → @(n, n0, n1) ∈ st; Used terms: @(m0, m1, m2), st[n, st[n].ref-size:= m]