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Proof step 26 from proof except-refsizeeq-trans (previous step)

(∅)[n] = mkblock(x0, lax0, m0), st0[n] = mkblock(x, lax, m), st1[n] = mkblock(x, lax, m1), n ∈ st1, n ∈ st0, ∀ n. (n ∈ st0 ↔ n ∈ st1) ∧ st0[n].list = st1[n].list ∧ st0[n].ladrlist = st1[n].ladrlist, ∀ n. (n ∈ st1 ↔ n ∈ st2) ∧ st1[n].list = st2[n].list ∧ st1[n].ladrlist = st2[n].ladrlist ⊦ n ∈ st2

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 7 terms: n

Additional information

Used terms: n