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Proof step 10 from proof except-refsizeeq-write-left (previous step)

n ∈ st0 ↔ n ∈ st1, st1[n] = mkblock(x0, lax0, m1), st0[n] = mkblock(x0, lax0, m0), ∀ n. (n ∈ st0 ↔ n ∈ st1) ∧ st0[n].list = st1[n].list ∧ st0[n].ladrlist = st1[n].ladrlist, ∀ n0. (n0 ∈ st0[n, mkblock(x, lax, m)] ↔ n0 ∈ st1) ∧ st0[n, mkblock(x, lax, m)][n0].list = st1[n0].list ∧ st0[n, mkblock(x, lax, m)][n0].ladrlist = st1[n0].ladrlist ⊦ n ∈ st1 ∧ x = x0 ∧ lax = lax0

Heuristic quantifier applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: n

Additional information

Used simplifier rules: ⊦ n ∈ st[n, ablock]; (s)% ⊦ st[n, ablock][n] = ablock; (s)% ⊦ mkblock(x, lax, m).list = x; (s)% ⊦ mkblock(x, lax, m).ladrlist = lax; (s) Used terms: n