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Proof step 11 from proof except-refsizeeq-write-left (previous step)

n ∈ st0 ↔ n ∈ st1, st1[n] = mkblock(x0, lax0, m1), st0[n] = mkblock(x0, lax0, m0), lax = lax0, x = x0, n ∈ st1, ∀ n. (n ∈ st0 ↔ n ∈ st1) ∧ st0[n].list = st1[n].list ∧ st0[n].ladrlist = st1[n].ladrlist ⊦ ∀ n0. (n0 ∈ st0[n, mkblock(x, lax, m)] ↔ n0 ∈ st1) ∧ st0[n, mkblock(x, lax, m)][n0].list = st1[n0].list ∧ st0[n, mkblock(x, lax, m)][n0].ladrlist = st1[n0].ladrlist

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
st0[n] = mkblock(x0, lax0, m0), st1[n] = mkblock(x0, lax0, m1), n ∈ st1, n ∈ st0, ∀ n. (n ∈ st0 ↔ n ∈ st1) ∧ st0[n].list = st1[n].list ∧ st0[n].ladrlist = st1[n].ladrlist ⊦ (n0 ∈ st0[n, mkblock(x0, lax0, m)] ↔ n0 ∈ st1) ∧ st0[n, mkblock(x0, lax0, m)][n0].list = st1[n0].list ∧ st0[n, mkblock(x0, lax0, m)][n0].ladrlist = st1[n0].ladrlist

Proof step 11 from proof except-refsizeeq-write-left (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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