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Proof step 4 from proof in-alloc (previous step)

adr = @(m, m0, m1), @(m0, m1) ∈ st[m].ladrlist, m ∈ st ⊦ adr ∈ st[n, ablock], n ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
m ∈ st, @(m0, m1) ∈ st[m].ladrlist ⊦ n ∈ st, @(m, m0, m1) ∈ st[n, ablock]

Rule argument

Additional information