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Proof step 3 from proof in-diff (previous step)

⊦ @(m, m0, m1) ∈ st \ ns ↔ @(m, m0, m1) ∈ st ∧ ¬ m ∈ ns

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ adr ∈ st ↔ adr.lnum ∈ st ∧ @(adr.pos, adr.size) ∈ st[adr.lnum].ladrlist
Proof step 5:
⊦ @(m, m0, m1).lnum ∈ st \ ns ∧ @(@(m, m0, m1).pos, @(m, m0, m1).size) ∈ (st \ ns)[@(m, m0, m1).lnum].ladrlist ↔ @(m, m0, m1) ∈ st ∧ ¬ m ∈ ns

Rule argument

spec: <toplevel> name: in seq: ⊦ adr ∈ st ↔ adr.lnum ∈ st ∧ @(adr.pos, adr.size) ∈ st[adr.lnum].ladrlist subst: [st, adr] → [st \ ns, @(m, m0, m1)] flags: <all paths>

Additional information

Used terms: st \ ns, @(m, m0, m1)