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Proof step 11 from proof in-write-refsize (previous step)

st[n, st[n].ref-size:= m][m0] = mkblock(x, lax, m3), n ∈ st ⊦ m0 ∈ st[n, st[n].ref-size:= m] ∧ @(m1, m2) ∈ lax ↔ m0 ∈ st ∧ @(m1, m2) ∈ st[m0].ladrlist

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 12:
st[n, st[n].ref-size:= m][m0] = mkblock(x, lax, m3), st[m0] = mkblock(x0, lax0, m4), n ∈ st ⊦ m0 ∈ st[n, st[n].ref-size:= m] ∧ @(m1, m2) ∈ lax ↔ m0 ∈ st ∧ @(m1, m2) ∈ lax0

Rule argument

spec: ablock name: elim seq: ⊦ (x = ablock.list ∧ lax = ablock.ladrlist) ∧ m = ablock.ref-size ↔ ablock = mkblock(x, lax, m) subst: [ablock, x, lax, m, m0, m1, boolvar] → [st[m0], x0, lax0, m6, m7, m8, boolvar0]

Additional information

Used simplifier rules: ⊦ (x = ablock.list ∧ lax = ablock.ladrlist) ∧ m = ablock.ref-size ↔ ablock = mkblock(x, lax, m); (elim) Used terms: st[m0], x0, lax0, m6, m7, m8, boolvar0