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Proof step 8 from proof in-write-same (previous step)

st[n] = mkblock(x, lax, m0), n ∈ st ⊦ m1 ∈ st[n, mkblock(x, lax, m)] ∧ @(m2, m3) ∈ st[n, mkblock(x, lax, m)][m1].ladrlist ↔ @(m1, m2, m3) ∈ st

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 9:
st[n] = mkblock(x, lax, m0), st[n, mkblock(x, lax, m)][m1] = mkblock(x0, lax0, m4), n ∈ st ⊦ m1 ∈ st[n, mkblock(x, lax, m)] ∧ @(m2, m3) ∈ lax0 ↔ @(m1, m2, m3) ∈ st

Rule argument

spec: ablock name: elim seq: ⊦ (x = ablock.list ∧ lax = ablock.ladrlist) ∧ m = ablock.ref-size ↔ ablock = mkblock(x, lax, m) subst: [ablock, x, lax, m] → [st[n, mkblock(x, lax, m)][m1], x0, lax0, m4]

Additional information

Used simplifier rules: ⊦ (x = ablock.list ∧ lax = ablock.ladrlist) ∧ m = ablock.ref-size ↔ ablock = mkblock(x, lax, m); (elim) Used terms: st[n, mkblock(x, lax, m)][m1], x0, lax0, m4