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Proof step 17 from proof inv-alloc (previous step)

(st[n, mkblock(x, lax, m)] \ (ns -- n))[n0] = mkblock(x0, lax0, m0), inv-flashsize(x, lax), n0 ∈ st[n, mkblock(x, lax, m)], ∀ n0. n0 ∈ st \ ns → # (st \ ns)[n0].list = # (st \ ns)[n0].ladrlist ∧ inv-flashsize((st \ ns)[n0].list, (st \ ns)[n0].ladrlist) ∧ ¬ dups((st \ ns)[n0].ladrlist), n0 = n ∨ ¬ n0 ∈ ns ⊦ dups(lax), inv-flashsize(x0, lax0) ∧ ¬ dups(lax0)

Heuristic nonsplitting cut applied rule cut formula

And obtained the following new goals

Rule argument

fma: n0 ∈ ns -- n

Additional information

Used simplifier rules: ⊦ n ∈ ns → (st \ ns)[n] = (∅)[n]; (s)% ⊦ n ∈ ns -- n0 ↔ n ≠ n0 ∧ n ∈ ns; (s)% ⊦ n ≠ n0 → (n ∈ st[n0, ablock] ↔ n ∈ st); (s) Used formulas: n0 ∈ ns -- n