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Proof step 4 from proof inv-alloc (previous step)

ablock = mkblock(x, lax, m), ∀ n0. n0 ∈ st \ ns → # (st \ ns)[n0].list = # (st \ ns)[n0].ladrlist ∧ inv-flashsize((st \ ns)[n0].list, (st \ ns)[n0].ladrlist) ∧ ¬ dups((st \ ns)[n0].ladrlist) ⊦ (∀ n0. n0 ∈ st[n, ablock] \ (ns -- n) → inv-flashsize((st[n, ablock] \ (ns -- n))[n0].list, (st[n, ablock] \ (ns -- n))[n0].ladrlist) ∧ ¬ dups((st[n, ablock] \ (ns -- n))[n0].ladrlist)) ↔ inv-flashsize(x, lax) ∧ ¬ dups(lax)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
∀ n0. n0 ∈ st \ ns → # (st \ ns)[n0].list = # (st \ ns)[n0].ladrlist ∧ inv-flashsize((st \ ns)[n0].list, (st \ ns)[n0].ladrlist) ∧ ¬ dups((st \ ns)[n0].ladrlist) ⊦ (∀ n0. n0 ∈ st[n, mkblock(x, lax, m)] \ (ns -- n) → inv-flashsize((st[n, mkblock(x, lax, m)] \ (ns -- n))[n0].list, (st[n, mkblock(x, lax, m)] \ (ns -- n))[n0].ladrlist) ∧ ¬ dups((st[n, mkblock(x, lax, m)] \ (ns -- n))[n0].ladrlist)) ↔ inv-flashsize(x, lax) ∧ ¬ dups(lax)

Proof step 4 from proof inv-alloc (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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