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Proof step 15 from proof inv-flashsize-app (previous step)

# x0 = # lax0, # x1 = # lax1, (lax0 + lax1)[n] = @(m, m0), n < # x0, n < # lax0 + # lax1, ∀ n. n < # lax1 → lax1[n].size = x1[n].flashsize, ∀ n. n < # lax0 → lax0[n].size = x0[n].flashsize ⊦ m0 = (x0 + x1)[n].flashsize

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
# x0 = # lax0, # x1 = # lax1, lax0[n] = @(m, m0), n < # lax0, n < # lax0 + # lax1, ∀ n. n < # lax1 → lax1[n].size = x1[n].flashsize, ∀ n. n < # lax0 → lax0[n].size = x0[n].flashsize ⊦ lax0 = [], m0 = x0[n].flashsize

Rule argument

Additional information

Used simplifier rules: ⊦ # lax = 0 ↔ lax = []; (s)%a: ⊦ (lax + lax0) + lax1 = lax + lax0 + lax1; from specification list[laddress-list]% ⊦ n < # lax → (lax + lax0)[n] = lax[n]; (s)%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ n < # x → (x + y)[n] = x[n]; (s)