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Proof step 20 from proof inv-flashsize-app (previous step)

# x1 = # lax1, # x0 = # lax0, lax1[n0] = @(m, m0), n0 < # lax1, ∀ n. n < # lax0 → lax0[n].size = x0[n].flashsize, ∀ n. n < # lax1 → lax1[n].size = x1[n].flashsize ⊦ lax1 = [], m0 = x1[n0].flashsize

User applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: n0 abort: F discard: T computed: T

Additional information

Used simplifier rules: ⊦ @(m, m0).size = m0; (s) Used terms: n0