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Proof step 15 from proof inv-flashsize-prepend (previous step)

# x = # lax, lax[n] = @(m1, m2), n < # lax, ∀ n. ¬ # lax < n → (@(m, a.flashsize) ' + lax)[n].size = (a ' + x)[n].flashsize ⊦ lax = [], m2 = x[n].flashsize

User applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: n + 1 abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ m < n + 1 ↔ ¬ n < m; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ (ladr ' + lax)[n + 1] = lax[n]; (s)%a: ⊦ (lax + lax0) + lax1 = lax + lax0 + lax1; from specification list[laddress-list]% ⊦ (a ' + x)[n + 1] = x[n]; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ @(m, m0).size = m0; (s) Used terms: n + 1