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Proof step 20 from proof inv-flashsize-prepend (previous step)

# x = # lax, (@(m, a.flashsize) ' + lax)[n] = @(m0, m1), n ≤ # lax, ∀ n. n < # lax → lax[n].size = x[n].flashsize ⊦ m1 = x[n - # a '].flashsize, n < # a '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
# x = # lax, (@(m, a.flashsize) ' + lax)[n] = @(m0, m1), n ≤ # lax, ∀ n. n < # lax → lax[n].size = x[n].flashsize ⊦ m1 = x[n - 1].flashsize, n = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m < 1 ↔ m = 0; (s)% ⊦ # a ' = 0 +1; (s)