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Proof step 2 from proof inv-listlen-ls1 (previous step)

# x < # lax, inv(mkblock(x, lax, m0)) ⊦

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: inv-block: ⊦ inv(ablock) ↔ # ablock.list = # ablock.ladrlist ∧ inv-flashsize(ablock.list, ablock.ladrlist) ∧ ¬ dups(ablock.ladrlist);% ⊦ m < n → ¬ n < m; (s)% ⊦ # lax = 0 ↔ lax = []; (s)%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic%lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ mkblock(x, lax, m).ladrlist = lax; (s)% ⊦ mkblock(x, lax, m).list = x; (s)