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Proof step 2 from proof inv-prefixn-lax (previous step)

inv(mkblock(x, lax, m0)) ⊦ prefixn(# x, lax) = lax

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: inv-listlen-ls1: ⊦ inv(mkblock(x, lax, m0)) → ¬ # x < # lax;%# lax ≤ m ⊦ prefixn(m, lax) = lax; (s)% ⊦ m ≤ n ↔ ¬ n < m; (ss)