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Proof step 3 from proof prefix-alloc (previous step)

∀ n1. n1 ∈ st → # st[n1].list = # st[n1].ladrlist ∧ inv-flashsize(st[n1].list, st[n1].ladrlist) ∧ ¬ dups(st[n1].ladrlist) ⊦ n ∈ st, st ⊑ st[n, mkblock(x, lax, n0)]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ st0 ⊑ st ↔ dom st0 ⊆ dom st ∧ (∀ n. n ∈ st0 ∧ n ∈ st → st0[n].list ⊑ st[n].list ∧ st0[n].ladrlist ⊑ st[n].ladrlist ∧ # st0[n].list = # st0[n].ladrlist ∧ # st[n].list = # st[n].ladrlist)
Proof step 5:
∀ n1. n1 ∈ st → # st[n1].list = # st[n1].ladrlist ∧ inv-flashsize(st[n1].list, st[n1].ladrlist) ∧ ¬ dups(st[n1].ladrlist) ⊦ n ∈ st, dom st ⊆ dom st[n, mkblock(x, lax, n0)] ∧ (∀ n1. n1 ∈ st ∧ n1 ∈ st[n, mkblock(x, lax, n0)] → st[n1].list ⊑ st[n, mkblock(x, lax, n0)][n1].list ∧ st[n1].ladrlist ⊑ st[n, mkblock(x, lax, n0)][n1].ladrlist ∧ # st[n1].list = # st[n1].ladrlist ∧ # st[n, mkblock(x, lax, n0)][n1].list = # st[n, mkblock(x, lax, n0)][n1].ladrlist)

Rule argument

spec: <toplevel> name: blockstore-prefix seq: ⊦ st0 ⊑ st ↔ dom st0 ⊆ dom st ∧ (∀ n. n ∈ st0 ∧ n ∈ st → st0[n].list ⊑ st[n].list ∧ st0[n].ladrlist ⊑ st[n].ladrlist ∧ # st0[n].list = # st0[n].ladrlist ∧ # st[n].list = # st[n].ladrlist) subst: [st, st0] → [st[n, mkblock(x, lax, n0)], st] flags: <all paths>

Additional information

Used terms: st[n, mkblock(x, lax, n0)], st