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Proof step 2 from proof prefix-append-notin (previous step)

st0 ⊑ st ⊦ n ∈ st, st0 ⊑ st[n, ablock]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
dom st0 ⊆ dom st, ∀ n. n ∈ st0 ∧ n ∈ st → st0[n].list ⊑ st[n].list ∧ st0[n].ladrlist ⊑ st[n].ladrlist ∧ # st0[n].list = # st0[n].ladrlist ∧ # st[n].list = # st[n].ladrlist ⊦ n ∈ st, st0 ⊑ st[n, ablock]

Rule argument

Additional information

Used simplifier rules: blockstore-prefix: ⊦ st0 ⊑ st ↔ dom st0 ⊆ dom st ∧ (∀ n. n ∈ st0 ∧ n ∈ st → st0[n].list ⊑ st[n].list ∧ st0[n].ladrlist ⊑ st[n].ladrlist ∧ # st0[n].list = # st0[n].ladrlist ∧ # st[n].list = # st[n].ladrlist);