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Proof step 13 from proof prefix-at (previous step)

st1[m] = mkblock(x0, lax0, m3), st0[m] = mkblock(x, lax, m2), m ∈ st0, @(m0, m1) ∈ lax, m ∈ st1 → x ⊑ x0 ∧ lax ⊑ lax0 ∧ # x = # lax ∧ # x0 = # lax0, m ∈ st0 → m ∈ st1, ∀ n. n ∈ st0 → n ∈ st1 ⊦ x[pos(@(m0, m1), lax)] = st1[@(m, m0, m1)]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
# x = # lax, # x0 = # lax0, st0[m] = mkblock(x, lax, m2), st1[m] = mkblock(x0, lax0, m3), @(m0, m1) ∈ lax, m ∈ st0, m ∈ st1, x ⊑ x0, lax ⊑ lax0, ∀ n. n ∈ st0 → n ∈ st1 ⊦ x[pos(@(m0, m1), lax)] = st1[@(m, m0, m1)]

Proof step 13 from proof prefix-at (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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