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Proof step 19 from proof prefix-at (previous step)

# x = # lax2 + # lax1 + 1, # x0 = # lax0, st1[m] = mkblock(x0, lax0, m3), st0[m] = mkblock(x, lax2 + @(m0, m1) ' + lax1, m2), m ∈ st1, m ∈ st0, lax2 + @(m0, m1) ' + lax1 ⊑ lax0, x ⊑ x0, ∀ n. n ∈ st0 → n ∈ st1 ⊦ x[# lax2] = st1[@(m, m0, m1)], @(m0, m1) ∈ lax2, @(m, m0, m1) ∈ st1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
# x0 = # lax0, # x = # lax2 + # lax1 + 1, st0[m] = mkblock(x, lax2 + @(m0, m1) ' + lax1, m2), st1[m] = mkblock(x0, lax0, m3), m ∈ st0, m ∈ st1, x ⊑ x0, lax2 + @(m0, m1) ' + lax1 ⊑ lax0, ∀ n. n ∈ st0 → n ∈ st1 ⊦ x[# lax2] = st1[@(m, m0, m1)], @(m, m0, m1) ∈ st1, @(m0, m1) ∈ lax2

Proof step 19 from proof prefix-at (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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