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Proof step 7 from proof prefix-del-right (previous step)

⊦ dom st ⊆ dom st0 -- m ∧ (∀ n. n ∈ st ∧ n ≠ m ∧ n ∈ st0 → st[n].list ⊑ st0[n].list ∧ st[n].ladrlist ⊑ st0[n].ladrlist ∧ # st[n].list = # st[n].ladrlist ∧ # st0[n].list = # st0[n].ladrlist) ↔ ( dom st ⊆ dom st0 ∧ (∀ n. n ∈ st ∧ n ∈ st0 → st[n].list ⊑ st0[n].list ∧ st[n].ladrlist ⊑ st0[n].ladrlist ∧ # st[n].list = # st[n].ladrlist ∧ # st0[n].list = # st0[n].ladrlist)) ∧ ¬ m ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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