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Proof step 2 from proof prefix-fwd-in (previous step)

n ∈ st0, st0 ⊑ st1 ⊦ n ∈ st1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n ∈ st0, dom st0 ⊆ dom st1, ∀ n. n ∈ st0 ∧ n ∈ st1 → st0[n].list ⊑ st1[n].list ∧ st0[n].ladrlist ⊑ st1[n].ladrlist ∧ # st0[n].list = # st0[n].ladrlist ∧ # st1[n].list = # st1[n].ladrlist ⊦ n ∈ st1

Rule argument

Additional information

Used simplifier rules: blockstore-prefix: ⊦ st0 ⊑ st ↔ dom st0 ⊆ dom st ∧ (∀ n. n ∈ st0 ∧ n ∈ st → st0[n].list ⊑ st[n].list ∧ st0[n].ladrlist ⊑ st[n].ladrlist ∧ # st0[n].list = # st0[n].ladrlist ∧ # st[n].list = # st[n].ladrlist);