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Proof step 13 from proof prefix-notin-fwd (previous step)

# st1[m].list = # st1[m].ladrlist, # x = # lax, st0[m] = mkblock(x, lax, m2), m ∈ st1, m ∈ st0, @(m0, m1) ∈ lax, lax ⊑ st1[m].ladrlist, x ⊑ st1[m].list ⊦ @(m, m0, m1) ∈ st1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 14:
# x = # lax, # x0 = # lax0, st0[m] = mkblock(x, lax, m2), st1[m] = mkblock(x0, lax0, m3), @(m0, m1) ∈ lax, m ∈ st0, m ∈ st1, x ⊑ x0, lax ⊑ lax0 ⊦ @(m, m0, m1) ∈ st1

Rule argument

spec: ablock name: elim seq: ⊦ (x = ablock.list ∧ lax = ablock.ladrlist) ∧ m = ablock.ref-size ↔ ablock = mkblock(x, lax, m) subst: [ablock, x, lax, m] → [st1[m], x0, lax0, m3]

Additional information

Used simplifier rules: ⊦ (x = ablock.list ∧ lax = ablock.ladrlist) ∧ m = ablock.ref-size ↔ ablock = mkblock(x, lax, m); (elim) Used terms: st1[m], x0, lax0, m3