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Proof step 2 from proof prefix-remove-refsize0 (previous step)

inv(st) ⊦ remove-refsize0(st) ⊑ st

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ st0 ⊑ st ↔ dom st0 ⊆ dom st ∧ (∀ n. n ∈ st0 ∧ n ∈ st → st0[n].list ⊑ st[n].list ∧ st0[n].ladrlist ⊑ st[n].ladrlist ∧ # st0[n].list = # st0[n].ladrlist ∧ # st[n].list = # st[n].ladrlist)
Proof step 4:
inv(st) ⊦ dom remove-refsize0(st) ⊆ dom st ∧ (∀ n. n ∈ remove-refsize0(st) ∧ n ∈ st → remove-refsize0(st)[n].list ⊑ st[n].list ∧ remove-refsize0(st)[n].ladrlist ⊑ st[n].ladrlist ∧ # remove-refsize0(st)[n].list = # remove-refsize0(st)[n].ladrlist ∧ # st[n].list = # st[n].ladrlist)

Rule argument

spec: <toplevel> name: blockstore-prefix seq: ⊦ st0 ⊑ st ↔ dom st0 ⊆ dom st ∧ (∀ n. n ∈ st0 ∧ n ∈ st → st0[n].list ⊑ st[n].list ∧ st0[n].ladrlist ⊑ st[n].ladrlist ∧ # st0[n].list = # st0[n].ladrlist ∧ # st[n].list = # st[n].ladrlist) subst: [st, st0] → [st, remove-refsize0(st)] flags: <all paths>

Additional information

Used terms: st, remove-refsize0(st)