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Proof step 13 from proof prefix-trans (previous step)

st1[n] = mkblock(x1, lax1, m1), st2[n] = mkblock(x0, lax0, m0), st0[n] = mkblock(x, lax, m), n ∈ st2, n ∈ st0, dom st1 ⊆ dom st2, dom st0 ⊆ dom st2, n ∈ st1 → x1 ⊑ x0 ∧ lax1 ⊑ lax0 ∧ # x1 = # lax1 ∧ # x0 = # lax0, n ∈ st1 → x ⊑ x1 ∧ lax ⊑ lax1 ∧ # x = # lax ∧ # x1 = # lax1, ∀ n0. n0 ∈ st0 → n0 ∈ st1 ⊦ x ⊑ x0 ∧ lax ⊑ lax0 ∧ # x = # lax ∧ # x0 = # lax0

User applied rule all left

And closed the goal!

Rule argument

pos: left 10 terms: n abort: F discard: F computed: T

Additional information

Used simplifier rules: prefix-trans: ⊦ lax ⊑ lax0 ∧ lax0 ⊑ lax1 → lax ⊑ lax1; (forward) from specification list-last[laddress-list]%prefix-trans: ⊦ x ⊑ y ∧ y ⊑ z → x ⊑ z; (forward) from specification list-last Used terms: n