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Proof step 1 from proof prefixn-to-adrs (conclusion)

⊦ prefixn(n, lax.to-adr(m)) = prefixn(n, lax).to-adr(m)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ prefixn(n, ax) = (n ≤ # ax ⊃ firstn(n, ax);ax)
Proof step 3:
⊦ (n ≤ # lax.to-adr(m) ⊃ firstn(n, lax.to-adr(m));lax.to-adr(m)) = prefixn(n, lax).to-adr(m)

Rule argument

spec: list-prefixn, inst: address-list-set name: prefixn seq: ⊦ prefixn(n, ax) = (n ≤ # ax ⊃ firstn(n, ax);ax) subst: [ax, n] → [lax.to-adr(m), n] flags: <all paths>

Additional information

Used terms: lax.to-adr(m), n