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Proof step 10 from proof prefixn-to-adrs (previous step)
| ⊦ firstn(# lax0, lax0.to-adr(m) + lax1.to-adr(m)) = lax0.to-adr(m) |
User applied rule insert rewrite lemma
And obtained the following new goals
- Proof step 11:
⊦ m ≤ # ax → firstn(m, ax + ax0) = firstn(m, ax)
- Proof step 12:
# lax0 ≤ # lax0.to-adr(m) ⊦ firstn(# lax0, lax0.to-adr(m)) = lax0.to-adr(m)
Rule argument
spec: list-del, inst: address-list-set
name: first-append
seq: ⊦ m ≤ # ax → firstn(m, ax + ax0) = firstn(m, ax)
subst: [ax0, ax, m] → [lax1.to-adr(m), lax0.to-adr(m), # lax0]
flags: <all paths>Additional information
Used simplifier rules:
addresslist-length: ⊦ # lax.to-adr(n) = # lax;% ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ ¬ n < n; (s)
Used terms: lax1.to-adr(m), lax0.to-adr(m), # lax0