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Proof step 7 from proof prefixn-to-adrs (
previous step
)
n ≤ # lax ⊦ firstn(n, lax.to-adr(m)) = (n ≤ # lax ⊃ firstn(n, lax);lax).to-adr(m)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 8
:
n ≤ # lax ⊦ firstn(n, lax.to-adr(m)) = firstn(n, lax).to-adr(m)
Rule argument
Additional information