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Proof step 3 from proof remove-refsize0-idem (previous step)

⊦ ∀ n. (n ∈ remove-refsize0(remove-refsize0(st)) ↔ n ∈ remove-refsize0(st)) ∧ (n ∈ remove-refsize0(remove-refsize0(st)) → remove-refsize0(remove-refsize0(st))[n] = remove-refsize0(st)[n])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information