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Proof step 8 from proof remove-refsize0-one (previous step)

(∅)[n, mkblock(x, lax, m0)][n0] = mkblock(x0, lax0, m) ⊦ (n0 ∈ (∅)[n, mkblock(x, lax, m0)] ∧ m ≠ 0 ↔ n0 ∈ (m0 = 0 ⊃ ∅;(∅)[n, mkblock(x, lax, m0)])) ∧ (n0 ∈ (∅)[n, mkblock(x, lax, m0)] ∧ m ≠ 0 → (∅)[n, mkblock(x, lax, m0)][n0] = (m0 = 0 ⊃ ∅;(∅)[n, mkblock(x, lax, m0)])[n0])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
(∅)[n, mkblock(x, lax, m0)][n0] = mkblock(x0, lax0, m) ⊦ (n0 ∈ (∅)[n, mkblock(x, lax, m0)] ∧ m ≠ 0 ↔ n0 ∈ (m0 = 0 ⊃ ∅;(∅)[n, mkblock(x, lax, m0)])) ∧ (n0 ∈ (∅)[n, mkblock(x, lax, m0)] ∧ m ≠ 0 → mkblock(x0, lax0, m) = (m0 = 0 ⊃ ∅;(∅)[n, mkblock(x, lax, m0)])[n0])

Proof step 8 from proof remove-refsize0-one (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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