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Proof step 8 from proof to-adrs-drop (previous step)

∀ n, m. dropn(n, lax0.to-adr(m)) = dropn(n, lax0).to-adr(m) ⊦ dropn(n - 1, lax0.to-adr(m)) = dropn(n, @(m0, m1) ' + lax0).to-adr(m), n = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 9:
n = m2 + 1, ∀ n, m. dropn(n, lax0.to-adr(m)) = dropn(n, lax0).to-adr(m) ⊦ dropn(m2, lax0.to-adr(m)) = dropn(n, @(m0, m1) ' + lax0).to-adr(m), n = 0

Rule argument

spec: nat name: elim-pred-c seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [n, m2]

Additional information

Used simplifier rules: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: n, m2