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Proof step 10 from proof to-adrs-eq-app (previous step)

lax1.to-adr(n) = lax0.to-adr(n) + @(n, m0, m1) ', @(m0, m1) ∈ lax1, ∀ n, lax, m0, m1. lax1.to-adr(n) = lax.to-adr(n) + @(n, m0, m1) ' ∧ @(m0, m1) ∈ lax1 → lax1 = lax + @(m0, m1) ' ⊦ lax1 = lax0 + @(m0, m1) '

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: n, lax0, m0, m1

Additional information

Used terms: n, lax0, m0, m1