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Proof step 10 from proof to-adrs-eq (previous step)

lax.to-adr(n) = lax0.to-adr(n), ∀ n, lax1. lax.to-adr(n) = lax1.to-adr(n) → lax = lax1 ⊦ lax = lax0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: n, lax0

Additional information

Used terms: n, lax0