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Proof step 2 from proof to-adrs-eq (previous step)

lax0.to-adr(n) = lax1.to-adr(n) ⊦ lax0 = lax1

User applied rule structural induction

And obtained the following new goals

Proof step 3:
(ladr + lax).to-adr(n) = lax1.to-adr(n), ∀ n, lax1. lax.to-adr(n) = lax1.to-adr(n) → lax = lax1 ⊦ ladr + lax = lax1

Rule argument

indvar: lax0

Additional information

Used simplifier rules: adrs-empty: ⊦ ([]).to-adr(n) = [];%to-adrs-eq-empty: ⊦ lax.to-adr(n) = [] ↔ lax = [];%laddress-list freely generated by [], +;;