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Proof step 7 from proof to-adrs-in (previous step)

@(m, m0, m1) ∈ lax0.to-adr(n) ↔ m = n ∧ @(m0, m1) ∈ lax0, @(m, m0, m1) = @(n, m2, m3) ∨ @(m, m0, m1) ∈ lax0.to-adr(n) ⊦ m = n ∧ (@(m0, m1) = @(m2, m3) ∨ @(m0, m1) ∈ lax0)

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ @(m, m0, m1) = @(m2, m3, m4) ↔ m = m2 ∧ m0 = m3 ∧ m1 = m4; (ws)