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Proof step 5 from proof to-adrs-sublist (previous step)

n0 + n1 ≤ # lax0 + 1, ∀ n0, n1, n. n0 + n1 ≤ # lax0 → sublist(n0, n1, lax0.to-adr(n)) = sublist(n0, n1, lax0).to-adr(n) ⊦ sublist(n0, n1, @(n, m, m0) ' + lax0.to-adr(n)) = sublist(n0, n1, @(m, m0) ' + lax0).to-adr(n)

User applied rule constructor cut

And obtained the following new goals

Proof step 6:
n0 = 0, n0 + n1 ≤ # lax0 + 1, ∀ n0, n1, n. n0 + n1 ≤ # lax0 → sublist(n0, n1, lax0.to-adr(n)) = sublist(n0, n1, lax0).to-adr(n) ⊦ sublist(n0, n1, @(n, m, m0) ' + lax0.to-adr(n)) = sublist(n0, n1, @(m, m0) ' + lax0).to-adr(n)
Proof step 16:
n0 = n2 +1, n0 + n1 ≤ # lax0 + 1, ∀ n0, n1, n. n0 + n1 ≤ # lax0 → sublist(n0, n1, lax0.to-adr(n)) = sublist(n0, n1, lax0).to-adr(n) ⊦ sublist(n0, n1, @(n, m, m0) ' + lax0.to-adr(n)) = sublist(n0, n1, @(m, m0) ' + lax0).to-adr(n)

Rule argument

var: n0

Additional information

Used simplifier rules: nat freely generated by 0, +1;;