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Proof step 6 from proof to-ards-no-dups (previous step)

dups(lax0), ∀ n. dups(lax0.to-adr(n)) ↔ dups(lax0) ⊦ @(n, m, m0) ∈ lax0.to-adr(n) ∨ dups(lax0.to-adr(n)) ↔ @(m, m0) ∈ lax0 ∨ dups(lax0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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