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Proof step 28 from proof in-remove-refsize0-refsize-cons (previous step)

# x0 = # lax0, (∅)[m] = mkblock(x, lax, m2), st[m] = mkblock(x0, lax0, 0), m ∈ st, @(m, m0, 0) ∈ as, @(m, m0, 0) ∈ st, ∀ n. n < # x0 → lax0[n].size = x0[n].flashsize ⊦ # as = 0, as = ∅, dups(lax0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
# x0 = # lax0, st[m] = mkblock(x0, lax0, 0), (∅)[m] = mkblock(x, lax, m2), @(m, m0, 0) ∈ st, @(m, m0, 0) ∈ as, m ∈ st, ∀ n. n < # lax0 → lax0[n].size = x0[n].flashsize ⊦ # as = 0, as = ∅, dups(lax0)

Proof step 28 from proof in-remove-refsize0-refsize-cons (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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