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Proof step 3 from proof in-remove-refsize0-refsize-cons (previous step)

inv(st), adr ∈ as, adr ∈ st, ∀ n. n ∈ st → st[n].ref-size = (as | n).size ⊦ # as = 0, as = ∅, adr ∈ remove-refsize0(st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ adr ∈ st ↔ adr.lnum ∈ st ∧ @(adr.pos, adr.size) ∈ st[adr.lnum].ladrlist
Proof step 5:
inv(st), adr ∈ st, adr ∈ as, ∀ n. n ∈ st → st[n].ref-size = (as | n).size ⊦ # as = 0, as = ∅, adr.lnum ∈ remove-refsize0(st) ∧ @(adr.pos, adr.size) ∈ remove-refsize0(st)[adr.lnum].ladrlist

Rule argument

spec: ablock-store-inv name: in seq: ⊦ adr ∈ st ↔ adr.lnum ∈ st ∧ @(adr.pos, adr.size) ∈ st[adr.lnum].ladrlist subst: [st, adr] → [remove-refsize0(st), adr] flags: <all paths>

Additional information

Used terms: remove-refsize0(st), adr