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Proof step 3 from proof inv-valid-adrs (previous step)

adr.size = 0, inv(st), adr ∈ as, adr ∈ st, as ⊆ dom nodes(st) ⊦ # as = 0, as = ∅

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
adr = @(m, m0, m1), m1 = 0, inv(st), adr ∈ st, adr ∈ as, as ⊆ dom nodes(st) ⊦ # as = 0, as = ∅

Rule argument

spec: address-data name: elim seq: ⊦ (m = adr.lnum ∧ m0 = adr.pos) ∧ m1 = adr.size ↔ adr = @(m, m0, m1) subst: [adr, m, m0, m1] → [adr, m, m0, m1]

Additional information

Used simplifier rules: ⊦ (m = adr.lnum ∧ m0 = adr.pos) ∧ m1 = adr.size ↔ adr = @(m, m0, m1); (elim) Used terms: adr, m, m0, m1