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Proof step 1 from proof refsize-cons-write (conclusion)

⊦ refsize-cons(st, as) → (refsize-cons(st[n, ablock], as) ↔ ¬ n ∈ st ∨ st[n].ref-size = (as | n).size → ablock.ref-size = (as | n).size)

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information