[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 10 from proof remove-refsize0-refsize-cons (previous step)

st[m].ref-size = (as | m).size, inv(st), @(m, m0, m1) ∈ st, @(m, m0, m1) ∈ as, m ∈ st, as ⊆ dom nodes(st) ⊦ # as = 0, as = ∅, @(m, m0, m1) ∈ remove-refsize0(st), dom nodes(st) ⊆ dom nodes(remove-refsize0(st))

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 11:
st[m] = mkblock(x, lax, m2), m2 = (as | m).size, inv(st), m ∈ st, @(m, m0, m1) ∈ as, @(m, m0, m1) ∈ st, as ⊆ dom nodes(st) ⊦ # as = 0, as = ∅, @(m, m0, m1) ∈ remove-refsize0(st), dom nodes(st) ⊆ dom nodes(remove-refsize0(st))

Rule argument

spec: ablock name: elim seq: ⊦ (x = ablock.list ∧ lax = ablock.ladrlist) ∧ m = ablock.ref-size ↔ ablock = mkblock(x, lax, m) subst: [ablock, x, lax, m] → [st[m], x, lax, m2]

Additional information

Used simplifier rules: ⊦ (x = ablock.list ∧ lax = ablock.ladrlist) ∧ m = ablock.ref-size ↔ ablock = mkblock(x, lax, m); (elim) Used terms: st[m], x, lax, m2